(4+y)(5y^2-4+4y)=

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Solution for (4+y)(5y^2-4+4y)= equation: 


Simplifying
(4 + y)(5y2 + -4 + 4y) = 0

Reorder the terms:
(4 + y)(-4 + 4y + 5y2) = 0

Multiply (4 + y) * (-4 + 4y + 5y2)
(4(-4 + 4y + 5y2) + y(-4 + 4y + 5y2)) = 0
((-4 * 4 + 4y * 4 + 5y2 * 4) + y(-4 + 4y + 5y2)) = 0
((-16 + 16y + 20y2) + y(-4 + 4y + 5y2)) = 0
(-16 + 16y + 20y2 + (-4 * y + 4y * y + 5y2 * y)) = 0
(-16 + 16y + 20y2 + (-4y + 4y2 + 5y3)) = 0

Reorder the terms:
(-16 + 16y + -4y + 20y2 + 4y2 + 5y3) = 0

Combine like terms: 16y + -4y = 12y
(-16 + 12y + 20y2 + 4y2 + 5y3) = 0

Combine like terms: 20y2 + 4y2 = 24y2
(-16 + 12y + 24y2 + 5y3) = 0

Solving
-16 + 12y + 24y2 + 5y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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